`(2, 1), -2x + y = 2` Find the distance between the point and the line.

The formula to determine the distance from a point `(x_o, y_o)` to a line Ax+By+C=0 is:

`d=|Ax_o + By_o + C|/sqrt(A^2+B^2)`

To apply, set one side of the given equation equal to zero.

`-2x+y=2`

`-2x+y-2=0`

Then, plug-in the coefficients of x and y, as well as the constant to the formula.

`d=|(-2)x_o + 1y_o + (-2)|/sqrt((-2)^2+1^2)`

`d=|-2x_o + y_o - 2|/sqrt5`

And, plug-in the given point (2,1).

`d=|-2(2)+1-2|/sqrt5`

`d=|-5|/sqrt5`

`d=5/sqrt5`

`d=5/sqrt5*sqrt5/sqrt5`

`d=(5sqrt5)/5`

`d=sqrt5`

Therefore, the distance between the point (2,1) and the line is `sqrt5` units.