`(-1, 2), 5x + 3y = -4` Find the distance between the point and the line.

Given (-1, 2) `5x+3y=-4`

`5x+3y=-4`

`5x+3y+4=0`

Let A=5, B=3, C=4, x1=-1, and y1=2

Find the distance between the point and the line using the formula

`d=|Ax_1+By_1+C|/sqrt(A^2+B^2)`

`d=|(5)(-1)+(3)(2)+4|/sqrt(5^2+3^2)`

`d=|-5+6+4|/sqrt(34)=5/sqrt(34)=.8575`

The distance between the point and the line is .8575 units.