`int_0^(pi/4) tan^4(t) dt` Evaluate the integral

`int_0^(pi/4) tan^4(t) dt`

Express the integrand in factor form.

`= int _0^(pi/4) tan^2(t) *tan^2(t) dt`

Plug-in the trigonometric identity `tan^2(t) = sec^2(t)-1` to one of the factors.

`= int_0^(pi/4) tan^2(t)*(sec^2(t)-1) dt`

`= int_0^(pi/4) (tan^2(t)sec^2(t)-tan^2(t)) dt`

`= int _0^(pi/4) tan^2(t)sec^2(t) dt - int_0^(pi/4)tan^2(t) dt`

Plug-in again the trigonometric identity  `tan^2(t) =sec^2(t) - 1` to the second integral.

`= int_0^(pi/4) tan^2(t)sec^2(t)dt- int_0^(pi/4) (sec^2(t) - 1) dt`

`= int_0^(pi/4) tan^2(t) sec^2(t) dt - int_0^(pi/4) sec^2(t)dt + int_0^(pi/4) dt`

For the first integral, apply the u-substitution method.

     `u=tan (t)`

     `du = sec^2(t) dt`

>> `int tan^2(t) sec^2(t)dt = int u^2du=u^3/3 = (tan^3(t))/3`

For the second integral, apply the formula `int sec^2 x dx = tanx` .

>> `int sec^2(t)dt = tan (t)`

And for the third integral, apply the formula `int adx = ax` .

`gtgt int dt = t`

So the integral becomes:

`int_0^(pi/4) tan^2(t) sec^2(t) dt - int_0^(pi/4) sec^2(t)dt + int_0^(pi/4) dt`

`= ((tan^3(t))/3 -tan(t) + t) |_0^(pi/4)`

`=((tan^3(pi/4))/3 - tan(pi/4) + pi/4) - ((tan^3(0))/3 - tan(0) + 0)`

`= (1/3 - 1 + pi/4) - 0`

`=pi/4 - 2/3`

Therefore,   `int_0^(pi/4) tan^4(t) dt = pi/4 - 2/3` .