`(3, 2), y = 2x - 1` Find the distance between the point and the line.

Given (3, 2) `y=2x-1`

`y=2x-1`

`-2x+y+1=0`

Let A=-2, B=1, C=1, x1=3, and y1=2

Find the distance between the point and the line using the formula

`d=|Ax_1+By_1+C|/sqrt(A^2+B^2)`

`d=|(-2)(3)+(1)(2)+1|/sqrt((-2)^2+1^2)`

`d=|-6+2+1|/sqrt(4+1)=3/sqrt5=1.3`

The distance between the point and the line is 1.3 units.