Hello!
I'm sure that all the doors are distinguishable, i.e. "enter the first red door" and "enter the second red door" are different events.
Then we can 1) enter a red door, leave (through) a green door or 2) enter a green door, leave a red door. The quantities of path in this two options must be added.
There are `5-2=3` green doors. For the option 1, we can enter each of `2` red doors and for each of them can leave through any of `3` green doors, so there are `2*3=6` paths. For the option 2, we can enter each of `3` green doors, leave through any of `2` red doors, again `3*2=6` paths.
And there are `6+6=12 ` paths total. This is the answer.
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