Friday, October 19, 2012

`int dx/(cos(x) - 1)` Evaluate the integral

`intdx/(cosx-1)=`


``Multiply by the conjugate of the denominator.


`int1/(cosx-1)*(cosx+1)/(cosx+1)dx=`


`int(cosx+1)/(cos^2x-1)dx=`


``Simplify, then integrate.


`int(cosx+1)/(-sin^2x)dx=` 


`intcosx/(-sin^2x)dx+int1/(-sin^2x)dx=`


`intcosx/(-sinxsinx)dx+int(-csc^2x)dx=`


`int(-cotxcscx-csc^2x)dx=`


`cscx+cotx+C`

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