There are 33 moles of oxygen in how many grams of Mg(BrO3)2?

Magnesium bromate, Mg(BrO3)2, is a molecule made up of magnesium, bromine and oxygen. The number of atoms of each species in the molecule are:

number of atoms of magnesium = 1

number of atoms of bromine = 1 x 2 = 2

number of atoms of oxygen = 3 x 2 = 6

Thus, each molecule of magnesium bromate contains 6 atoms of oxygen. We can also say that 1 mole of magnesium bromate contains 6 moles of oxygen.

If 6 moles of oxygen are in 1 mole of magnesium bromate,

33 moles of oxygen will be in (1/6) x 33 = 5.5 moles of magnesium bromate.

The molar mass of magnesium bromate = 24.3 + 2 x 79.9 + 6 x 16 = 280.1 g/mole

Thus, 5.5 moles of magnesium bromate = 5.5 x 280.1 = 1,540.55 g

Thus, 1,540.55 g of magnesium bromate contains 33 moles of oxygen.

Hope this helps.