For E(st.cell) = +1.10V.
E(st.cell) here is the standard potential. Given the concentrations for the ions of copper and zinc as 0.001M and 0.1M respectively, the Nernst equation can be used to calculate E as follows:
where n is the number of electrons transferred, and in this case is 2, and Q is the reaction quotient, or the ratio of concentrations of ion products to ion reactants. In this case, Q will be [Zn2+]/[Cu2+] = 0.1/0.001 = 100.
R is the universal gas constant: 8.314 J/molK
F is Faraday's constant: 96, 485 C/mol
T is temperature in kelvin.
No temperature is given, but I will assume that this is STP so that temperature is 25C or 298K.
Then,
.
Therefore, the cell potential is +1.04V.
Note that I assumed the temperature to be 298K. If the temperature is different, simply change the temperature, but the entire process remains the same.
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