`(2, 3), 3x + y = 1` Find the distance between the point and the line.

Given (2, 3)  `3x+y=1`

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`3x+y=1`

`3x+y-1=0`

Let A=3, B=1, C=-1, x1=2, and y1=3.

Find the distance between a point and a line using the formula

`d=|Ax_1+By_1+C|/sqrt(A^2+B^2)`

`d=|(3)(2)+(1)(3)+(-1)|/sqrt(3^2+1^2)=|6+3-1|/sqrt(10)=8/sqrt10=2.5`

The distance between the point and the line is 2.5 units.