`(4, -4), y = -2x - 3` Find the distance between the point and the line.

The formula to determine the distance from a point (xo,yo) to a line Ax+By+C=0 is:

`d=|Ax_o + By_o + C|/sqrt(A^2+B^2)`

To apply, set one side of the given equation equal to zero.

`y=-2x-3`

`2x+y+3=0`

Then, plug-in the coefficients of x and y, as well as the constant to the formula.

`d=|2x_o +1y_o +3|/sqrt(2^2+1^2)`

`d=|2x_o + y_o +3|/sqrt5`

And, plug-in the given point (4,-4).

`d=|2(4)+(-4)+3|/sqrt5`

`d=7/sqrt5`

`d=7/sqrt5*sqrt5/sqrt5`

`d=(7sqrt5)/5`

Therefore, the point (4,-4) is `(7sqrt5)/5` units away from the line y=-2x-3.