`(2, 1), y = x + 2` Find the distance between the point and the line.

Take note that the formula to determine the distance from a point (xo, yo) to a line Ax+By+C=0 is:

`d = |Ax_o + By_o +C|/sqrt(A^2+B^2)`

To apply, set one side of the given equation equal to zero.

`y=x+2`

`0=x-y+2`

Then, plug-in the coefficients of x and y, as well as the constant to the formula.

`d=|1x_0 + (-1)y_o +2|/sqrt(1^2+(-1)^2)`

`d=|x_o -y_o + 2|/sqrt2`

And, plug-in the given point (2,1).

`d=|2-1+2|/sqrt2`

`d=|3|/sqrt2`

`d=3/sqrt2`

`d=3/sqrt2*sqrt2/sqrt2`

`d=(3sqrt2)/2`

Therefore, the distance between the point (2,1) and the line y=x+2 is  `(3sqrt2)/2` units.