We have three components in series; component A has reliability .9, component B has reliability of .98 and we are asked to find the reliability of component C if the total system reliability is .8379:
The reliability of the series of components is found by multiplying the reliabilities of each of the components. If x is the reliability of component C then we have:
(.9)(.98)x=.8379
.882x=.8379 Dividing both sides by .882 we get x=.95
The reliability of component C is .95 or 95%
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