How many milliliters of water are needed to make a 0.711 M solution that contains 1.00 g of NaCl?

Molarity is equal to the number of moles of solute per liters of solution.

   Molarity (M) = moles (mol)/liter (L) 

Step 1: Rearrange the formula to solve for liters.

First, multiply both sides of the formula by 1/moles. "moles" cancels out on the right side of the formula giving us:

   Molarity (M)/moles (mol) = 1/liters (L)

Next, flip both sides of the formula:

   moles (mol)/Molarity (M) = liters (L)/1

Finally, rewrite the formula so that the unknown variable (liters) is on the left side of the formula:

     liters (L) = moles (mol)/Molarity (M)

Step 2: Change grams to moles.

First, we will need to calculate the molar mass of the substance (NaCl). The molar mass of a substance is calculated by multiplying each atom's subscript by its atomic mass, and adding the resulting products together:

   Molar mass of NaCl = (1)(22.990) + (1)(35.453) = 58.443 g/mol

Next, convert the given grams of NaCl (1.00 g) to moles by dividing by the molar mass of NaCl:

  1.00 g x 1 mol/58.443 g = 0.0171 mol NaCl

Step 3: Use the rearranged molarity formula from Step 1 to solve for liters (L).

   liters (L) = moles (mol)/Molarity (M)

   liters (L) = 0.0171/0.711 M = 0.0241 L

Step 4: Convert liters to milliliters by moving the decimal point three places to the right.

   0.0241 L = 24.1 mL of water