Monday, March 30, 2009

If a solution of Sr(OH)2 has a concentration of 4.8E-5M, what is the concentration of its hydroxide ion? a cannot be determined; it does not...

Each molecule of strontium hydroxide, `Sr(OH)_2` , consists of 1 strontium ion (`Sr^2+`) and 2 hydroxide ions (`OH^-`). Therefore, the concentration of strontium ions is the same as that of strontium hydroxide, while the concentration of hydroxide ions would be twice that much.


Here, the concentration of strontium hydroxide is given as 4.8E-5 M or 4.8 x 10^-5 M. In other words, there are 4.8 x 10^-5 moles of strontium hydroxide in one liter of the solution. This also means that there would be 4.8 x 10^-5 moles of strontium ions and 2 x (4.8 x 10^-5) = 9.6 x 10^-5 moles of hydroxide ions in one liter of that solution.


This means that the concentration of hydroxide ions for this solution is 9.6 x 10^-5 M or 9.6E-5 M.


Thus, among the given options, choice B is correct.


Hope this helps.

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