What are the ionic equations for the reaction of permanganate with Fe2+?

The reaction of permanganate with Fe2+ is an oxidation-reduction reaction, since permanganate is an oxidizing agent. Hence, Fe2+ will get oxidized, while the permanganate will get reduced. 

The oxidation reaction can be written as:

`Fe^(2+) -> Fe^(3+) + e^-`

Here, Fe2+ oxidizes to Fe3+ and thus its oxidation number changes from +2 to +3.

The reduction reaction can be written as:

`MnO_4^(-) -> Mn^(2+)`

Here, the oxidation number of Mn changes from +7 to +2 and it gets reduced. The balanced chemical reaction for reduction can be written as:

`MnO_4^(-) + 8H^(+) + 5e^(-) -> Mn^(2+) + 4H_2O`

The overall chemical reaction can be written by combining the equations for oxidation and reduction (in such a way that the electrons balance out) as:

`5Fe^(2+) + MnO_4^(-) + 8H^(+) -> 5Fe^(3+) + Mn^(2+) + 4H_2O`

Hope this helps.