Sunday, March 1, 2015

0.30 g of citric acid is dissolved in distilled water to produce 100.0 mL of a 0.016 M solution. How much citric acid is needed in order to...

The balanced chemical reaction for this problem is:




First, we need to get how many moles of sodium bicarbonate to be neutralized. 


Moles of NaHCO3 = 





To get the moles of citric acid (C6H8O7) that will react with 0.15 moles of NaHCO3 = 




Now we can solve for the amount of citric acid needed to completely react with sodium bicarbonate.


(1) In terms of mass:





(2) In terms of the citric acid solution:


Molarity = moles/volume of solution


Volume of solution = moles citric acid/molarity of the citric acid solution


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