`(-1, -5), 6x + 3y = 3` Find the distance between the point and the line.

Given (-1, -5)  `6x+3y=3`

`6x+3y=3`

`6x+3y-3=0`

`2x+y-1=0`

A=2, B=1, C=-1, x1=-1, and y1=-5

Find the distance between the point and the line using the formula

`d=|Ax_1+By_2+C|/sqrt(A^2+B^2)`

`d=|(2)(-1)+(1)(-5)+(-1)|/sqrt(2^2+1^2)`

`d=|-2-5-1|/sqrt(5)=8/sqrt5=3.6`

The distance between the point and the line is 3.6 units.