The following reaction results in the required products:
`Ba(NO_3)_2 (aq) + Na_2SO_4 (aq) -> BaSO_4 (s) + 2 NaNO_3 (aq)`
In this reaction, barium nitrate reacts with sodium sulphate and generates barium sulphate and sodium nitrate.
If you look closely, you will notice that the cations (barium and sodium) and anions (nitrate and sulphate) remain the same, their respective partners have been changed. For example, on the reactant side, barium is bonded with nitrate ion, while sodium is bonded with sulphate. However, on the product side of the equation, barium is bonded with sulphate and sodium is bonded with nitrate. That is, barium has replaced its anion (nitrate) with that of sodium and sodium has done the same. Thus, this reaction is an example of double displacement and hence this reaction can be classified as a double displacement reaction.
Hope this helps.
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