`(6, 2), -3x + 4y = -5` Find the distance between the point and the line.

Given (6, 2), `-3x+4y=-5`

`-3x+4y=-5`

`-3x+4y+5=0`

Let A=-3, B=4, C=5, x1=6, and y1=2

Find the distance between the point and the line using the formula

`d=|Ax_1+By_1+C|/sqrt(A^2+B^2)`

`d=|(-3)(6)+(4)(2)+5|/ [sqrt((-3)^2+(4^2))]`

`d=|-18+8+5|/sqrt(9+16)=5/5=1`

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The distance between the point and the line is 1 unit.