To solve, apply the thin lens equation.
`1/f = 1/d_o + 1/d_i`
where
f = len's focal length
`d_o` = object distance
`d_i` = image distance
Plugging in the given values, the formula becomes:
`1/f=1/10 +1/15`
`1/f=1/10*3/3 + 1/15*2/2`
`1/f=3/30 + 2/30`
`1/f=5/30`
`1/f=1/6`
`f=6`
Therefore, the focal length of the lens is 6 cm.
Take note that a converging lens has a positive value for f. And a diverging lens has a negative value for f.
Since the resulting value of f is positive, then, the it is a converging lens.
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